*+**** Marie--Woods entered math111e_Room1. Tuesday, April 3, 2007 5:45pm
 
*+**** Bill--Beck entered math111e_Room1. Tuesday, April 3, 2007 5:52pm
 
*-**** Bill--Beck left math111e_Room1. Tuesday, April 3, 2007 5:52pm
 
*+**** Bill--Beck entered math111e_Room1. Tuesday, April 3, 2007 5:52pm
 
Bill  Beck>>Hi, Jim and Marie!
 
Marie  Woods>>Hi, I looked over ch 10 and have so many questions
 
Bill  Beck>>Well, I'm the guy with the answers!
 
Marie  Woods>>First of all, when you get the measurements or numbers between 0 and whatever how do you come up with the figure? I don't get it
 
Marie  Woods>>I mean the numbers in the curve?
 
Bill  Beck>>Let's go through tonight's walkthru and maybe that will answer your questions, Marie.
 
Marie  Woods>>Thanks
 
Bill  Beck>>Are we all on Walk21_p1?
 
Marie  Woods>>yes
 
Bill  Beck>>Are you with us, Jim?
 
Bill  Beck>>I think Jim went out for a beer.
 
Bill  Beck>>Let's go to page 2, please.
 
Marie  Woods>>maybe so
 
Bill  Beck>>I've sketched the graph of this distribution.
 
Marie  Woods>>II see this, but how do you measure the darkened area?
 
Bill  Beck>>Notice that the high point of the graph (the mode) is at about .02 or .03
 
Bill  Beck>>Hang in there with me, Marie.
 
Marie  Woods>>yes
 
Bill  Beck>>Go to page 3, please.
 
Marie  Woods>>I will
 
Bill  Beck>>Go to page 4, please.
 
*+**** Tonia--Bussey entered math111e_Room1. Tuesday, April 3, 2007 5:59pm
 
*+**** David--Wells entered math111e_Room1. Tuesday, April 3, 2007 5:59pm
 
Bill  Beck>>Hi, Tonia and David!
 
David  Wells>>hello
 
Bill  Beck>>We're on Walk21 P4.
 
Bill  Beck>>Go to page 5, please.
 
Bill  Beck>>MATH 111 classes are sometimes bimodal also
 
Bill  Beck>>Lots of As and lots of Ds
 
Bill  Beck>>Go to page 6, please.
 
*-**** James--Boland left math111e_Room1. Tuesday, April 3, 2007 6:01pm
 
Bill  Beck>>For a "normal" distribution the mean, median, and mode are the same.
 
Bill  Beck>>We're going to spend some time looking at "normal" distributions tonight.
 
Bill  Beck>>Go to page 7, please.
 
Bill  Beck>>For example, if we know that the mean is 7 and the standard deviation is 2, then we know that 7+2 = 9 and 7 - 2 = 5 so we know that approximately 68% of the data lie between 9 and 5.
 
Bill  Beck>>Go to page 8, please.
 
*+**** Danny--Wells entered math111e_Room1. Tuesday, April 3, 2007 6:04pm
 
Bill  Beck>>And we know that 7+2(2)  =  7+4  =  11
 
Bill  Beck>>7 - 2(2)  =  7-4  =  3
 
Bill  Beck>>So we know that approximately 95% of the scores lie between 11 and 3.
 
Bill  Beck>>Hi, Danny!
 
Danny  Wells>>hello, what page are we on?
 
Bill  Beck>>Danny, we are on Walk21 p8
 
Danny  Wells>>thank you
 
Bill  Beck>>Go to page 9, please.
 
Bill  Beck>>So between 7 + 3(2) = 7 + 6  =  13
 
Bill  Beck>>and 7 - 3(2)  =  7 - 6  =  1
 
Bill  Beck>>Thus approximately 97.5% of the scores lie between 13 and 1.
 
Bill  Beck>>Marie wants to know where we get these figures!!!!
 
Marie  Woods>>please, do tell
 
Bill  Beck>>Right, Marie?
 
Marie  Woods>>yes
 
Bill  Beck>>Okay, let's reveal out secret.
 
Bill  Beck>>Let's click on Tools then Table, please.
 
Tonia  Bussey>>wow, there they are!
 
Marie  Woods>>I had no idea
 
Bill  Beck>>In the upper left hand corner of the table we see a graph with an area shaded red.
 
Marie  Woods>>Lets do one wiht the table, please
 
Bill  Beck>>That area is between some value called 0 and z
 
Bill  Beck>>Before we get into calculating z, let's see how we read this table.
 
Marie  Woods>>what is 0 and what is z on the table, give me an example
 
Marie  Woods>>I see z and A
 
Marie  Woods>>across the top of the tab le
 
Bill  Beck>>Let's read the table, then we'll worry about calculating z, Marie.
 
Bill  Beck>>Suppose z = .51
 
Marie  Woods>>okay
 
Bill  Beck>>Do you agree that A = .195?
 
Marie  Woods>>yes
 
Bill  Beck>>And if z = 1.15 do you agree that A = .375?
 
Marie  Woods>>yes
 
Marie  Woods>>I am seeing it now
 
Bill  Beck>>It turns out that z = (x - xbar)/s
 
Bill  Beck>>But we'll worry about that later.
 
Bill  Beck>>Let's click on "hide 'em" please.
 
Bill  Beck>>Go to page 10, please.
 
Bill  Beck>>Here I'm given a shaded region between z = 0 and z = 1.2
 
Marie  Woods>>okay
 
Bill  Beck>>We want to use the table to determine the area of that region.
 
Bill  Beck>>Go to page 11, please.
 
Bill  Beck>>Do you agree that A = .385?
 
Bill  Beck>>Do you know where I got that .385?
 
Bill  Beck>>Hmmmmm
 
Marie  Woods>>no
 
Bill  Beck>>Let's click on Tools, then Table, please.
 
Marie  Woods>>would it be reversing and finding A on the table
 
Tonia  Bussey>>yes, i see
 
Bill  Beck>>We need to scroll down to get z = 1.20
 
Marie  Woods>>It appears to easy
 
Bill  Beck>>And next to the z=1.20 do you see the A=3.85?
 
Marie  Woods>>yes
 
Bill  Beck>>Okay, let's click on "hide 'em" please.
 
Marie  Woods>>move the decimals from.385 to 3.85?
 
Bill  Beck>>This time we have a negative value for z
 
Bill  Beck>>No, That was a typo, Marie, it should be .385
 
Marie  Woods>>okay
 
Bill  Beck>>On page 12, we have a negative value for z
 
Bill  Beck>>Because of the symmetry of the normal curve, the area under the curve between z = 0 and z = -.55 is exactly the same as the area under the curve between z = 0 and z = .55
 
Bill  Beck>>So to the area between z = 0 and z = -.55, we just look at z = .55 in our table.
 
Bill  Beck>>What is our value?
 
Tonia  Bussey>>.209
 
Marie  Woods>>.209
 
Bill  Beck>>RIGHT
 
Bill  Beck>>Okay, let's go to page 13, please.
 
Bill  Beck>>Go to page 14, please.
 
Tonia  Bussey>>so anytime it is a negative, it is as if we apply it as a positive
 
Bill  Beck>>ALWAYS sketch a graph!
 
Bill  Beck>>Yes, Tonia.
 
Bill  Beck>>Go to page 15, please.
 
Tonia  Bussey>>okay, thanks
 
Bill  Beck>>Go to page 16, please.
 
Bill  Beck>>Hmmmmm
 
Bill  Beck>>This time I've sketched a graph that does not touch the line z = 0
 
Bill  Beck>>It is a "detached region."
 
Bill  Beck>>Go to page 17 to see how we determine the area when it is detached.
 
Bill  Beck>>abut means to touch.
 
Bill  Beck>>Go to page 18, please.
 
Bill  Beck>>We can use our table to determine the area between z=0 and z=1.83
 
Bill  Beck>>Go to page 19, please.
 
Bill  Beck>>We can use our table to determine the area between z=0 and z=.50
 
Bill  Beck>>Life is good!
 
Bill  Beck>>Go to page 20, please.
 
Marie  Woods>>so far
 
Bill  Beck>>Makes sense to me.  How about you?
 
Marie  Woods>>yes
 
Tonia  Bussey>>yep, i get it
 
Bill  Beck>>Go to page 21, please.
 
Bill  Beck>>If we look at z = 1.83 in our table, we see that A = .466
 
Bill  Beck>>Go to page 22, please.
 
Bill  Beck>>If we look at z = .50, we see that A = .192
 
Bill  Beck>>Go to page 23, please.
 
Bill  Beck>>A little subtraction gives us the area of the detached region.
 
Bill  Beck>>Make sense?
 
Marie  Woods>>wiith the tablet was really easer than I feared
 
Tonia  Bussey>>yes
 
Marie  Woods>>table
 
Bill  Beck>>Life is good when you have a copy of the table.
 
Bill  Beck>>I'll supply the table on Test 3!
 
Marie  Woods>>great
 
Bill  Beck>>Okay, let's go to the last walkthru for tonight, please.
 
Bill  Beck>>Let me know when you are on Walk22 p1, please.
 
Marie  Woods>>there
 
David  Wells>>there
 
Tonia  Bussey>>i'm there
 
Danny  Wells>>im there
 
Bill  Beck>>Go to page 2, please.
 
Bill  Beck>>The mean, 7.5 is at the center of the normal curve.
 
Bill  Beck>>7.3 is to the left of 7.5
 
Bill  Beck>>Go to page 3,please.
 
Bill  Beck>>Here's our formula for z
 
Bill  Beck>>I'll supply this formula on Test 3.
 
Bill  Beck>>Go to page 4, please.
 
Marie  Woods>>good
 
Bill  Beck>>Notice that z is a negative number.
 
Tonia  Bussey>>great
 
Bill  Beck>>That just means that our score, x, is to the left of the mean, xbar.
 
Bill  Beck>>Go to page 5, please.
 
Bill  Beck>>For z = .13, we get A = .052
 
Bill  Beck>>Okay?
 
Marie  Woods>>table again?
 
Bill  Beck>>yes
 
Bill  Beck>>Go to page 6, please
 
Marie  Woods>>on this problem will the negative number always be 1st
 
Bill  Beck>>Go to page 7, please.
 
Marie  Woods>>n the math
 
Bill  Beck>>Sketch a graph!
 
Bill  Beck>>The mean is in the middle of the graph
 
Bill  Beck>>Go to page 8, please.
 
Bill  Beck>>12 is to the right of 10
 
Bill  Beck>>And we want the region to the right of 12, so I've shaded the graph to the right of 12.
 
Bill  Beck>>Go to page 9, please.
 
Bill  Beck>>Remember, our table always has regions that abut z = 0
 
Bill  Beck>>Go to page 10, please.
 
Bill  Beck>>This is another region that abuts z = 0
 
Bill  Beck>>Go to page 11, please
 
Bill  Beck>>When we have a detached region, we need to subtract!
 
Bill  Beck>>Go to page 12, please.
 
Bill  Beck>>1/2 of the scores are to the right of the mean, median, and mode.
 
Bill  Beck>>Go to page 13, please.
 
Bill  Beck>>First we calculate z, then we use the table to determine A
 
Bill  Beck>>Go to page 14, please.
 
Bill  Beck>>Go to page 15, please.
 
Bill  Beck>>Make sense?
 
Tonia  Bussey>>got it
 
Marie  Woods>>sort of
 
Bill  Beck>>Go back and listen to the lectures again, Marie.
 
Bill  Beck>>Take good notes!!!
 
Bill  Beck>>Okay, Class, that's it for tonight.
 
Marie  Woods>>try again, where did .500 and .341 come from again?
 
Bill  Beck>>We don't have class next week - it's spring break.
 
Bill  Beck>>1/2 of the scores are greater than the median -- .500
 
Marie  Woods>>do we have homework due on Tuesday
 
Bill  Beck>>Then we calculated z = 1 for x = 12, so we used our table to get A = .341
 
Tonia  Bussey>>As always Bill, thanks!  Have a great spring break!!  :)
 
Bill  Beck>>Our next homework is due after the break.
 
Bill  Beck>>Have a good one, Tonia!
 
David  Wells>>good night
 
Tonia  Bussey>>:)
 
*-**** David--Wells left math111e_Room1. Tuesday, April 3, 2007 6:37pm
 
Bill  Beck>>G'night, David
 
*-**** Tonia--Bussey left math111e_Room1. Tuesday, April 3, 2007 6:37pm
 
*+**** Lisa--Despanza entered math111e_Room1. Tuesday, April 3, 2007 6:37pm
 
Danny  Wells>>bye, night
 
*-**** Danny--Wells left math111e_Room1. Tuesday, April 3, 2007 6:37pm
 
Marie  Woods>>help
 
Marie  Woods>>where does .500 come from again? on the table
 
Lisa  Despanza>>I was late, I guessed I missed everything
 
*+**** Bill--Beck entered math111e_Room1. Tuesday, April 3, 2007 6:38pm
 
Bill  Beck>>Lost my connection
 
Bill  Beck>>Are you still with me?
 
Lisa  Despanza>>yes
 
Marie  Woods>>I see 1 is .341, but which .500 is used?
 
Bill  Beck>>Marie, don't forget about the median
 
Bill  Beck>>The median is the point such that 50% of the scores are greater than the median and 50% of the scores are less than the median.
 
Bill  Beck>>For a normal curve the median, mean, and mode are the same.
 
Bill  Beck>>That's where the .500 comes from.
 
Bill  Beck>>Okay?
 
Marie  Woods>>I know you want to go, but I just don’t see it
 
*-**** Lisa--Despanza left math111e_Room1. Tuesday, April 3, 2007 6:42pm
 
Bill  Beck>>Marie, do you remember the definition of median?
 
Marie  Woods>>what number on the table is .500, maybe if I see it I will get iit
 
Marie  Woods>>I will check the definition again
 
Bill  Beck>>I'm talking about our lesson on mean, median and mode, Marie.
 
Marie  Woods>>yes
 
Bill  Beck>>Do you remember how we determined the median and what that number represented?
 
Marie  Woods>>I need to review
 
Bill  Beck>>The median is the number such that 1/2 of the scores are less than the median and 1/2 of the scores are greater than the median.
 
Marie  Woods>>okay
 
Bill  Beck>>Thus I don't need to use the table to determine that score.
 
Bill  Beck>>I know that 1/2 or .500 of the scores are less than the median and that 1/2 or .500 of the scores are greater than the median.
 
Bill  Beck>>I didn't use the table at all for that value.
 
Marie  Woods>>then its .250 either way, right? equaling .500
 
Bill  Beck>>No, it's .500 to the left of the median and .500 to the right of the median for 1.00
 
Marie  Woods>>I see now, we are usng.1 not 1 as a whole, so its 1 half f 1
 
Marie  Woods>>of 1
 
Bill  Beck>>That's right
 
Marie  Woods>>finially, sorry to keep you, have a great break
 
Marie  Woods>>thanks
 
Bill  Beck>>No problem, Marie, have a good break.
 
Bill  Beck>>G'night
 
Marie  Woods>>good nght
 
*-**** Marie--Woods left math111e_Room1. Tuesday, April 3, 2007 6:47pm
 
*-**** Bill--Beck left math111e_Room1. Tuesday, April 3, 2007 6:47pm
 
*-**** Bill--Beck left math111e_Room1. Tuesday, April 3, 2007 6:55pm
 
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Tuesday, April 3, 2007 6:55pm
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Wednesday, April 4, 2007 2:00pm
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*+**** Mira--Hickson entered math111e_Room1. Wednesday, April 4, 2007 2:00pm
 
*-**** Mira--Hickson left math111e_Room1. Wednesday, April 4, 2007 2:01pm
 
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Wednesday, April 4, 2007 2:01pm
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Wednesday, April 4, 2007 2:22pm
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*+**** Antoinette--Johnson entered math111e_Room1. Wednesday, April 4, 2007 2:22pm
 
*-**** Antoinette--Johnson left math111e_Room1. Wednesday, April 4, 2007 2:22pm
 
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Wednesday, April 4, 2007 2:22pm
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